2x^2-13x+40=0

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Solution for 2x^2-13x+40=0 equation:


Simplifying
2x2 + -13x + 40 = 0

Reorder the terms:
40 + -13x + 2x2 = 0

Solving
40 + -13x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
20 + -6.5x + x2 = 0

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + -6.5x + -20 + x2 = 0 + -20

Reorder the terms:
20 + -20 + -6.5x + x2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -6.5x + x2 = 0 + -20
-6.5x + x2 = 0 + -20

Combine like terms: 0 + -20 = -20
-6.5x + x2 = -20

The x term is -6.5x.  Take half its coefficient (-3.25).
Square it (10.5625) and add it to both sides.

Add '10.5625' to each side of the equation.
-6.5x + 10.5625 + x2 = -20 + 10.5625

Reorder the terms:
10.5625 + -6.5x + x2 = -20 + 10.5625

Combine like terms: -20 + 10.5625 = -9.4375
10.5625 + -6.5x + x2 = -9.4375

Factor a perfect square on the left side:
(x + -3.25)(x + -3.25) = -9.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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